Optimal. Leaf size=299 \[ -\frac{(3 a d+2 b c) \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )}{6 a^{5/3} c^2}+\frac{(3 a d+2 b c) \tan ^{-1}\left (\frac{2 \sqrt [3]{a+b x^3}+\sqrt [3]{a}}{\sqrt{3} \sqrt [3]{a}}\right )}{3 \sqrt{3} a^{5/3} c^2}+\frac{\log (x) (3 a d+2 b c)}{6 a^{5/3} c^2}-\frac{d^{5/3} \log \left (c+d x^3\right )}{6 c^2 (b c-a d)^{2/3}}+\frac{d^{5/3} \log \left (\sqrt [3]{b c-a d}+\sqrt [3]{d} \sqrt [3]{a+b x^3}\right )}{2 c^2 (b c-a d)^{2/3}}-\frac{d^{5/3} \tan ^{-1}\left (\frac{1-\frac{2 \sqrt [3]{d} \sqrt [3]{a+b x^3}}{\sqrt [3]{b c-a d}}}{\sqrt{3}}\right )}{\sqrt{3} c^2 (b c-a d)^{2/3}}-\frac{\sqrt [3]{a+b x^3}}{3 a c x^3} \]
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Rubi [A] time = 0.316702, antiderivative size = 299, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 8, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {446, 103, 156, 57, 617, 204, 31, 58} \[ -\frac{(3 a d+2 b c) \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )}{6 a^{5/3} c^2}+\frac{(3 a d+2 b c) \tan ^{-1}\left (\frac{2 \sqrt [3]{a+b x^3}+\sqrt [3]{a}}{\sqrt{3} \sqrt [3]{a}}\right )}{3 \sqrt{3} a^{5/3} c^2}+\frac{\log (x) (3 a d+2 b c)}{6 a^{5/3} c^2}-\frac{d^{5/3} \log \left (c+d x^3\right )}{6 c^2 (b c-a d)^{2/3}}+\frac{d^{5/3} \log \left (\sqrt [3]{b c-a d}+\sqrt [3]{d} \sqrt [3]{a+b x^3}\right )}{2 c^2 (b c-a d)^{2/3}}-\frac{d^{5/3} \tan ^{-1}\left (\frac{1-\frac{2 \sqrt [3]{d} \sqrt [3]{a+b x^3}}{\sqrt [3]{b c-a d}}}{\sqrt{3}}\right )}{\sqrt{3} c^2 (b c-a d)^{2/3}}-\frac{\sqrt [3]{a+b x^3}}{3 a c x^3} \]
Antiderivative was successfully verified.
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Rule 446
Rule 103
Rule 156
Rule 57
Rule 617
Rule 204
Rule 31
Rule 58
Rubi steps
\begin{align*} \int \frac{1}{x^4 \left (a+b x^3\right )^{2/3} \left (c+d x^3\right )} \, dx &=\frac{1}{3} \operatorname{Subst}\left (\int \frac{1}{x^2 (a+b x)^{2/3} (c+d x)} \, dx,x,x^3\right )\\ &=-\frac{\sqrt [3]{a+b x^3}}{3 a c x^3}-\frac{\operatorname{Subst}\left (\int \frac{\frac{1}{3} (2 b c+3 a d)+\frac{2 b d x}{3}}{x (a+b x)^{2/3} (c+d x)} \, dx,x,x^3\right )}{3 a c}\\ &=-\frac{\sqrt [3]{a+b x^3}}{3 a c x^3}+\frac{d^2 \operatorname{Subst}\left (\int \frac{1}{(a+b x)^{2/3} (c+d x)} \, dx,x,x^3\right )}{3 c^2}-\frac{(2 b c+3 a d) \operatorname{Subst}\left (\int \frac{1}{x (a+b x)^{2/3}} \, dx,x,x^3\right )}{9 a c^2}\\ &=-\frac{\sqrt [3]{a+b x^3}}{3 a c x^3}+\frac{(2 b c+3 a d) \log (x)}{6 a^{5/3} c^2}-\frac{d^{5/3} \log \left (c+d x^3\right )}{6 c^2 (b c-a d)^{2/3}}+\frac{d^{5/3} \operatorname{Subst}\left (\int \frac{1}{\frac{\sqrt [3]{b c-a d}}{\sqrt [3]{d}}+x} \, dx,x,\sqrt [3]{a+b x^3}\right )}{2 c^2 (b c-a d)^{2/3}}+\frac{d^{4/3} \operatorname{Subst}\left (\int \frac{1}{\frac{(b c-a d)^{2/3}}{d^{2/3}}-\frac{\sqrt [3]{b c-a d} x}{\sqrt [3]{d}}+x^2} \, dx,x,\sqrt [3]{a+b x^3}\right )}{2 c^2 \sqrt [3]{b c-a d}}+\frac{(2 b c+3 a d) \operatorname{Subst}\left (\int \frac{1}{\sqrt [3]{a}-x} \, dx,x,\sqrt [3]{a+b x^3}\right )}{6 a^{5/3} c^2}+\frac{(2 b c+3 a d) \operatorname{Subst}\left (\int \frac{1}{a^{2/3}+\sqrt [3]{a} x+x^2} \, dx,x,\sqrt [3]{a+b x^3}\right )}{6 a^{4/3} c^2}\\ &=-\frac{\sqrt [3]{a+b x^3}}{3 a c x^3}+\frac{(2 b c+3 a d) \log (x)}{6 a^{5/3} c^2}-\frac{d^{5/3} \log \left (c+d x^3\right )}{6 c^2 (b c-a d)^{2/3}}-\frac{(2 b c+3 a d) \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )}{6 a^{5/3} c^2}+\frac{d^{5/3} \log \left (\sqrt [3]{b c-a d}+\sqrt [3]{d} \sqrt [3]{a+b x^3}\right )}{2 c^2 (b c-a d)^{2/3}}+\frac{d^{5/3} \operatorname{Subst}\left (\int \frac{1}{-3-x^2} \, dx,x,1-\frac{2 \sqrt [3]{d} \sqrt [3]{a+b x^3}}{\sqrt [3]{b c-a d}}\right )}{c^2 (b c-a d)^{2/3}}-\frac{(2 b c+3 a d) \operatorname{Subst}\left (\int \frac{1}{-3-x^2} \, dx,x,1+\frac{2 \sqrt [3]{a+b x^3}}{\sqrt [3]{a}}\right )}{3 a^{5/3} c^2}\\ &=-\frac{\sqrt [3]{a+b x^3}}{3 a c x^3}+\frac{(2 b c+3 a d) \tan ^{-1}\left (\frac{1+\frac{2 \sqrt [3]{a+b x^3}}{\sqrt [3]{a}}}{\sqrt{3}}\right )}{3 \sqrt{3} a^{5/3} c^2}-\frac{d^{5/3} \tan ^{-1}\left (\frac{1-\frac{2 \sqrt [3]{d} \sqrt [3]{a+b x^3}}{\sqrt [3]{b c-a d}}}{\sqrt{3}}\right )}{\sqrt{3} c^2 (b c-a d)^{2/3}}+\frac{(2 b c+3 a d) \log (x)}{6 a^{5/3} c^2}-\frac{d^{5/3} \log \left (c+d x^3\right )}{6 c^2 (b c-a d)^{2/3}}-\frac{(2 b c+3 a d) \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )}{6 a^{5/3} c^2}+\frac{d^{5/3} \log \left (\sqrt [3]{b c-a d}+\sqrt [3]{d} \sqrt [3]{a+b x^3}\right )}{2 c^2 (b c-a d)^{2/3}}\\ \end{align*}
Mathematica [A] time = 0.416603, size = 303, normalized size = 1.01 \[ \frac{\frac{(3 a d+2 b c) \left (\log \left (a^{2/3}+\sqrt [3]{a} \sqrt [3]{a+b x^3}+\left (a+b x^3\right )^{2/3}\right )-2 \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )+2 \sqrt{3} \tan ^{-1}\left (\frac{\frac{2 \sqrt [3]{a+b x^3}}{\sqrt [3]{a}}+1}{\sqrt{3}}\right )\right )}{a^{2/3} c}+\frac{3 a d^{5/3} \left (-\log \left (-\sqrt [3]{d} \sqrt [3]{a+b x^3} \sqrt [3]{b c-a d}+(b c-a d)^{2/3}+d^{2/3} \left (a+b x^3\right )^{2/3}\right )+2 \log \left (\sqrt [3]{b c-a d}+\sqrt [3]{d} \sqrt [3]{a+b x^3}\right )+2 \sqrt{3} \tan ^{-1}\left (\frac{\frac{2 \sqrt [3]{d} \sqrt [3]{a+b x^3}}{\sqrt [3]{b c-a d}}-1}{\sqrt{3}}\right )\right )}{c (b c-a d)^{2/3}}-\frac{6 \sqrt [3]{a+b x^3}}{x^3}}{18 a c} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.059, size = 0, normalized size = 0. \begin{align*} \int{\frac{1}{{x}^{4} \left ( d{x}^{3}+c \right ) } \left ( b{x}^{3}+a \right ) ^{-{\frac{2}{3}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (b x^{3} + a\right )}^{\frac{2}{3}}{\left (d x^{3} + c\right )} x^{4}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 4.66328, size = 1296, normalized size = 4.33 \begin{align*} -\frac{6 \, \sqrt{3} a^{3} d \left (\frac{d^{2}}{b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}}\right )^{\frac{1}{3}} x^{3} \arctan \left (-\frac{2 \, \sqrt{3}{\left (b x^{3} + a\right )}^{\frac{1}{3}}{\left (b c - a d\right )} \left (\frac{d^{2}}{b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}}\right )^{\frac{2}{3}} - \sqrt{3} d}{3 \, d}\right ) + 3 \, a^{3} d \left (\frac{d^{2}}{b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}}\right )^{\frac{1}{3}} x^{3} \log \left ({\left (b x^{3} + a\right )}^{\frac{2}{3}} d^{2} -{\left (b x^{3} + a\right )}^{\frac{1}{3}}{\left (b c d - a d^{2}\right )} \left (\frac{d^{2}}{b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}}\right )^{\frac{1}{3}} +{\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} \left (\frac{d^{2}}{b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}}\right )^{\frac{2}{3}}\right ) - 6 \, a^{3} d \left (\frac{d^{2}}{b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}}\right )^{\frac{1}{3}} x^{3} \log \left ({\left (b x^{3} + a\right )}^{\frac{1}{3}} d +{\left (b c - a d\right )} \left (\frac{d^{2}}{b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}}\right )^{\frac{1}{3}}\right ) - 2 \, \sqrt{3}{\left (2 \, a b c + 3 \, a^{2} d\right )} x^{3} \sqrt{-\left (-a^{2}\right )^{\frac{1}{3}}} \arctan \left (-\frac{{\left (\sqrt{3} \left (-a^{2}\right )^{\frac{1}{3}} a - 2 \, \sqrt{3}{\left (b x^{3} + a\right )}^{\frac{1}{3}} \left (-a^{2}\right )^{\frac{2}{3}}\right )} \sqrt{-\left (-a^{2}\right )^{\frac{1}{3}}}}{3 \, a^{2}}\right ) - \left (-a^{2}\right )^{\frac{2}{3}}{\left (2 \, b c + 3 \, a d\right )} x^{3} \log \left ({\left (b x^{3} + a\right )}^{\frac{2}{3}} a - \left (-a^{2}\right )^{\frac{1}{3}} a +{\left (b x^{3} + a\right )}^{\frac{1}{3}} \left (-a^{2}\right )^{\frac{2}{3}}\right ) + 2 \, \left (-a^{2}\right )^{\frac{2}{3}}{\left (2 \, b c + 3 \, a d\right )} x^{3} \log \left ({\left (b x^{3} + a\right )}^{\frac{1}{3}} a - \left (-a^{2}\right )^{\frac{2}{3}}\right ) + 6 \,{\left (b x^{3} + a\right )}^{\frac{1}{3}} a^{2} c}{18 \, a^{3} c^{2} x^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{x^{4} \left (a + b x^{3}\right )^{\frac{2}{3}} \left (c + d x^{3}\right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 2.36861, size = 567, normalized size = 1.9 \begin{align*} -\frac{1}{18} \,{\left (\frac{6 \, d^{2} \left (-\frac{b c - a d}{d}\right )^{\frac{1}{3}} \log \left ({\left |{\left (b x^{3} + a\right )}^{\frac{1}{3}} - \left (-\frac{b c - a d}{d}\right )^{\frac{1}{3}} \right |}\right )}{b^{3} c^{3} - a b^{2} c^{2} d} - \frac{18 \,{\left (-b c d^{2} + a d^{3}\right )}^{\frac{1}{3}} d \arctan \left (\frac{\sqrt{3}{\left (2 \,{\left (b x^{3} + a\right )}^{\frac{1}{3}} + \left (-\frac{b c - a d}{d}\right )^{\frac{1}{3}}\right )}}{3 \, \left (-\frac{b c - a d}{d}\right )^{\frac{1}{3}}}\right )}{\sqrt{3} b^{3} c^{3} - \sqrt{3} a b^{2} c^{2} d} - \frac{3 \,{\left (-b c d^{2} + a d^{3}\right )}^{\frac{1}{3}} d \log \left ({\left (b x^{3} + a\right )}^{\frac{2}{3}} +{\left (b x^{3} + a\right )}^{\frac{1}{3}} \left (-\frac{b c - a d}{d}\right )^{\frac{1}{3}} + \left (-\frac{b c - a d}{d}\right )^{\frac{2}{3}}\right )}{b^{3} c^{3} - a b^{2} c^{2} d} - \frac{2 \, \sqrt{3}{\left (2 \, a^{\frac{1}{3}} b c + 3 \, a^{\frac{4}{3}} d\right )} \arctan \left (\frac{\sqrt{3}{\left (2 \,{\left (b x^{3} + a\right )}^{\frac{1}{3}} + a^{\frac{1}{3}}\right )}}{3 \, a^{\frac{1}{3}}}\right )}{a^{2} b^{2} c^{2}} + \frac{2 \,{\left (2 \, b c + 3 \, a d\right )} \log \left ({\left |{\left (b x^{3} + a\right )}^{\frac{1}{3}} - a^{\frac{1}{3}} \right |}\right )}{a^{\frac{5}{3}} b^{2} c^{2}} - \frac{{\left (2 \, a^{\frac{1}{3}} b c + 3 \, a^{\frac{4}{3}} d\right )} \log \left ({\left (b x^{3} + a\right )}^{\frac{2}{3}} +{\left (b x^{3} + a\right )}^{\frac{1}{3}} a^{\frac{1}{3}} + a^{\frac{2}{3}}\right )}{a^{2} b^{2} c^{2}} + \frac{6 \,{\left (b x^{3} + a\right )}^{\frac{1}{3}}}{a b^{2} c x^{3}}\right )} b^{2} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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